1,6665t^2-20t+60=0

Solution for 1,6665t^2-20t+60=0 equation:

1.6665t^2-20t+60=0

a = 1.6665; b = -20; c = +60;
Δ = b2-4ac
Δ = -202-4·1.6665·60
Δ = 0.039999999999964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-\sqrt{0.039999999999964}}{2*1.6665}=\frac{20-\sqrt{0.039999999999964}}{3.333}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+\sqrt{0.039999999999964}}{2*1.6665}=\frac{20+\sqrt{0.039999999999964}}{3.333}
$